Warning: Default Parameters
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Warning: Default Parameters#
In the last module, we learned about how to define default parameters for your function. What this means is we specify what a default value should be for a parameter and the client can optionally provide a value for that parameter (it takes the default value if not specified). For example,
def some_function(x, y=2):
print(x * y)
some_function(4, 5)
some_function(3) # default will be y=2
One important thing to mention: you are allowed to give default values for any parameter you want, however, there is a rule about the order of parameters when you define default values. If you define a default value for a parameter, every parameter after that one in the list of parameters must also have a default value. This means you would not be able to write a function like the one below. If you run it, you will see an error.
def some_function(a, b=2, c):
print(a * b * c)
A Curious Case#
Default parameters are great, but there is one case you have usually think about when you are programming in Python.
Suppose I wanted to write a function called append_to
that takes a value and a list
and appends the value to the end of the list, returning the list
back to the caller. Suppose we wanted to make the list
parameter optional, in which case the default value is the empty list. In the following cell, we define such a method and then call it a couple of times. Before you run the code snippet below, think about what this program should print out.
def append_to(element, to=[]):
to.append(element)
return to
my_list = append_to(12)
print(my_list)
my_other_list = append_to(42)
print(my_other_list)
If you’re like me, you would have expected it to print:
[12]
[42]
However, in reality, it prints:
[12]
[12, 42]
Don’t believe me? Try running it yourself!
What is going on?#
It turns out that when we specify the default parameter to=[]
, it only creates one list
instance that is shared between all calls to append_to
. If you think about drawing the memory model here, whenever you omit the to
parameter and it uses the default, it is always referring to the same list
instance! That means my_list
, my_other_list
and to
(only in the case when the default value is used) all refer to one list
object.
You can check out this website to see a visualization of the memory model for this program above.
At this point, some students might confuse this with creating a list regularly using the []
syntax. That is not the case. Each time you specify []
it makes a new empty list. The problem here is Python only evaluates the default-parameter once when the function is first loaded (before it’s called) so all function calls that use the default value share that one value for the default-parameter.
How do we fix this?#
The general pattern is to make the default value None
and then write code inside the method to create an empty list
if the value is None
. For example, the fixed code block using this pattern would look like:
def append_to(element, to=None):
if to is None:
to = []
to.append(element)
return to
my_list = append_to(12)
print(my_list)
my_other_list = append_to(42)
print(my_other_list)
And now it prints the output we expected originally! Each time append_to
was called and the default-value None
was used, we then created a new list
to return so there are now 2 list
objects in this program above.
Fancier Syntax#
It can be kind of tedious to sometimes write out an entire if-else block to set a value. Python has a conditional expression that lets you write this in shorter syntax (some call this the “ternary operator”). Below we show the original if-else block (the original way you’re familiar with) and then we show the conditional expression that achieve the same value assignment.
condition = True # Or any boolean value
# Option 1
if condition:
x = 14
else:
x = 42
print(x)
# Option 2
x = 14 if condition else 42
print(x)
The syntax looks a little weird at first, but it’s meant to read like English “x should have the value 14 if the condition is true, otherwise, it should be 42”.
We could then rewrite our append_to
example using this slightly cleaner syntax:
def append_to(element, to=None):
to = [] if to is None else to
to.append(element)
return to
my_list = append_to(12)
print(my_list)
my_other_list = append_to(42)
print(my_other_list)
Line 2 of this code block can be read to mean ” to
should reference a new list
if to is None
(the default), otherwise to
should be to
(whatever was passed to the call).